Searched refs:nAnzNums (Results 1 – 2 of 2) sorted by relevance
131 nAnzNums = 0; in Reset()385 nNums[nAnzNums] = nAnzStrings; in NumberStringDivision()386 nAnzNums++; in NumberStringDivision()2183 switch ( nAnzNums ) in IsNumberFormatMain()2570 if (nAnzNums > 2) in IsNumberFormat()2575 if (nAnzNums > 3) in IsNumberFormat()2583 if (nAnzNums > 4) in IsNumberFormat()2658 nAnzNums-1 : nAnzNums); in IsNumberFormat()2701 if (nAnzNums == 1) in IsNumberFormat()2703 else if (nAnzNums == 2) in IsNumberFormat()[all …]
60 sal_uInt16 GetAnzNums() const { return nAnzNums; } in GetAnzNums()81 sal_uInt16 nAnzNums; // Count of numeric substrings member in ImpSvNumberInputScan
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