Searched refs:nDiffSeconds (Results 1 – 1 of 1) sorted by relevance
89 long nDiffSeconds = aTimeNow.GetHour() * 3600 + aTimeNow.GetMin() * 60 + aTimeNow.GetSec(); in GetNow() local90 return (double)nDiffDays + ((double)nDiffSeconds)/(double)(24*3600); in GetNow()
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