Searched refs:nIndexOf (Results 1 – 2 of 2) sorted by relevance
198 sal_Int32 nIndexOf = sStr.indexOf(sFrom); in operate() local199 while( nIndexOf != -1 ) in operate()201 sStr = sStr.replaceAt(nIndexOf,sFrom.getLength(),sTo); in operate()202 nIndexOf = sStr.indexOf(sFrom,nIndexOf + sTo.getLength()); in operate()
1229 sal_Int32 nIndexOf = 0; in EndElement() local1232 nIndexOf = aEquationIter->indexOf( '?', nIndexOf ); in EndElement()1233 if ( nIndexOf != -1 ) in EndElement()1236 if ( GetEquationName( *aEquationIter, nIndexOf + 1, aEquationName ) ) in EndElement()1239 rtl::OUString aNew( aEquationIter->copy( 0, nIndexOf + 1 ) ); in EndElement()1245 aNew += aEquationIter->copy( nIndexOf + aEquationName.getLength() + 1 ); in EndElement()1248 nIndexOf++; in EndElement()1251 while( nIndexOf != -1 ); in EndElement()
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