Searched refs:aIt1 (Results 1 – 2 of 2) sorted by relevance
808 std::vector< PieLabelInfo >::iterator aIt1 = m_aLabelInfoList.begin(); in rearrangeLabelToAvoidOverlapIfRequested() local811 for( ;aIt1!=aEnd; ++aIt1 ) in rearrangeLabelToAvoidOverlapIfRequested()813 if(aIt1->bMovementAllowed) in rearrangeLabelToAvoidOverlapIfRequested()828 aIt1 = m_aLabelInfoList.begin(); in rearrangeLabelToAvoidOverlapIfRequested()829 std::vector< PieLabelInfo >::iterator aIt2 = aIt1; in rearrangeLabelToAvoidOverlapIfRequested()830 if( aIt1==aEnd )//no need to do anything when we only have one label in rearrangeLabelToAvoidOverlapIfRequested()832 aIt1->pPrevious = &(*(m_aLabelInfoList.rbegin())); in rearrangeLabelToAvoidOverlapIfRequested()834 for( ;aIt2!=aEnd; ++aIt1, ++aIt2 ) in rearrangeLabelToAvoidOverlapIfRequested()836 PieLabelInfo& rInfo1( *aIt1 ); in rearrangeLabelToAvoidOverlapIfRequested()841 aIt1->pNext = &(*(m_aLabelInfoList.begin())); in rearrangeLabelToAvoidOverlapIfRequested()[all …]
1820 java.util.Iterator aIt1 = m_lFilters.keySet().iterator(); in analyze() local1821 while (aIt1.hasNext()) in analyze()1823 java.lang.String sFilter = (java.lang.String)aIt1.next(); in analyze()1837 aIt1 = m_lTypes.keySet().iterator(); in analyze()1838 while (aIt1.hasNext()) in analyze()1840 java.lang.String sType = (java.lang.String)aIt1.next(); in analyze()1936 java.util.Iterator aIt1 = m_lTypes.keySet().iterator(); in validateTypes() local1937 while(aIt1.hasNext()) in validateTypes()1939 java.lang.String sType = (java.lang.String)aIt1.next(); in validateTypes()2020 java.util.Iterator aIt1 = m_lFilters.keySet().iterator(); in validateFilters() local[all …]