Searched refs:nNewClusterWidth (Results 1 – 2 of 2) sorted by relevance
1156 long nNewClusterWidth = args.mpDXArray[nLastChar]; in ApplyDXArray() local1162 nNewClusterWidth -= args.mpDXArray[nPrevClusterLastChar]; in ApplyDXArray()1166 long nDWidth = nNewClusterWidth - nOrigClusterWidth; in ApplyDXArray()1195 …g%d-%d dW%ld-%ld=%ld dX%ld x%ld\t", (int)i, nChar2Base, nLastGlyph, nNewClusterWidth, nOrigCluster… in ApplyDXArray()
1200 int nNewClusterWidth = pNewGlyphWidths[i]; in ApplyDXArray() local1208 nNewClusterWidth += pNewGlyphWidths[j]; in ApplyDXArray()1210 const int nDiff = nNewClusterWidth - nOldClusterWidth; in ApplyDXArray()1226 nNewPos += nNewClusterWidth; in ApplyDXArray()